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Projectile Motion Calculator

Find a projectile's range, time of flight, maximum height and landing speed from its launch speed, angle and height, with no air resistance.

Launch Speedunit
Launch Heightunit
Gravityunit

A thrown ball, a kicked football and a water jet all follow the same curved path. This calculator takes the launch speed, angle and height and works out how far the projectile goes, how long it’s in the air, how high it gets and how fast it lands, ignoring air resistance.

How to Use It

  1. Enter the Launch Speed and Launch Angle (0° is flat, 90° straight up).
  2. Enter the Launch Height above where it lands, or 0 for ground to ground.
  3. Leave Gravity at 9.81 m/s², or change it for another world.
  4. Choose the unit for Distances In and press Calculate.

How It Works

The launch speed splits into a horizontal and a vertical part:

vx=vcos⁡θvy=vsin⁡θv_x = \vA{v}\cos\vB{\theta} \qquad v_y = \vA{v}\sin\vB{\theta}

The horizontal part stays the same the whole way. Gravity slows the vertical part, so the time in the air solves h+vyt−12gt2=0h + v_y t - \tfrac{1}{2}gt^2 = 0:

t=vy+vy2+2ghgt = \frac{v_y + \sqrt{v_y^2 + 2g\vC{h}}}{g}

The range is vxtv_x t, the maximum height is h+vy22gh + \frac{v_y^2}{2g}, reached after vyg\frac{v_y}{g} seconds, and the landing speed is v2+2gh\sqrt{v^2 + 2gh}.

Worked Example

A ball is kicked at 20 m/s at 45° from the ground. Then vx=vy=20cos⁡45°≈14.14v_x = v_y = 20 \cos 45° \approx 14.14 m/s, and:

t=2×14.149.81≈2.88 srange=14.14×2.88≈40.8 mt = \frac{2 \times 14.14}{9.81} \approx 2.88 \text{ s} \qquad \text{range} = 14.14 \times 2.88 \approx 40.8 \text{ m}

It peaks at 14.1422×9.81≈10.2\frac{14.14^2}{2 \times 9.81} \approx 10.2 m after about 1.44 s.

Tips and Common Mistakes

  • Use the angle from the horizontal. A 30° launch means 30° above the ground, not from vertical.
  • Split the speed first. Only the vertical part is affected by gravity.
  • Height matters. A launch from a cliff stays up longer and lands faster than one from the ground.
  • 45° is best only for level ground. From a height, a lower angle usually goes farther.
  • Real flights are shorter. Air resistance slows real projectiles, especially light ones.

Frequently Asked Questions

What angle gives the longest range?

45°, when the projectile lands at the same height it was launched from. From a height, a slightly lower angle goes farther.

Why is the horizontal speed constant?

With no air resistance, nothing pushes sideways, so only the vertical speed changes as gravity pulls down.

How are the speed's parts found?

Horizontal speed = v cos θ and vertical speed = v sin θ, where θ is the launch angle.

Does it include air resistance?

No. Real projectiles, especially light or fast ones, fall shorter than this ideal path.

Why do 30° and 60° land in the same place?

From ground level, complementary angles (adding to 90°) give the same range: one flies low and fast, the other high and slow.

What if I launch from a cliff?

Enter the launch height. The object then falls farther than it rose, so it stays in the air longer and lands faster.

Sources

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